What is the radius x^2+y^2-6x-8y-3=0 ?

The radius x^2+y^2-6x-8y-3=0 is r=2sqrt(7)

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radius x^2+y^2-6x-8y-3=0

radius

x^{2} + y^{2} - 6 x - 8 y - 3 = 0

r = 27

Solution steps

x^{2} + y^{2} - 6 x - 8 y - 3 = 0

Rewrite

x^{2} + y^{2} - 6 x - 8 y - 3 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - 4)^{2} = (27)^{2}

Therefore the circle properties are:

(a, b) = (3, 4), r = 27

And the radius is:

r = 27

(x + 2)^{2} + y^{2} = 9

(x + 3)^{2} + y^{2} = 100

4 x^{2} + 4 y^{2} = 128

(x - 2)^{2} + (y - 1)^{2} = 49

2 (x + 1)^{2} + 2 (y - 3)^{2} = 5

What is the radius x^2+y^2-6x-8y-3=0 ?
The radius x^2+y^2-6x-8y-3=0 is r=2sqrt(7)