What is the radius x^2+y^2-14x-2y=50 ?

The radius x^2+y^2-14x-2y=50 is r=10

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radius x^2+y^2-14x-2y=50

radius

x^{2} + y^{2} - 14 x - 2 y = 50

r = 10

Solution steps

x^{2} + y^{2} - 14 x - 2 y = 50

Rewrite

x^{2} + y^{2} - 14 x - 2 y = 50

in the form of the standard circle equation

(x - 7)^{2} + (y - 1)^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (7, 1), r = 10

And the radius is:

r = 10

(x - 6)^{2} + (y - 2)^{2} = 16

x^{2} + y^{2} + 4 x + 6 y - 51 = 0

5 x^{2} + 5 y^{2} = 25

x^{2} + y^{2} - 10 x + 16 y + 85 = 0

4 (x + 5)^{2} + 4 (y + 4)^{2} - 20 = 0