What is the radius x^2+y^2-2x-6y-15=0 ?

The radius x^2+y^2-2x-6y-15=0 is r=5

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radius x^2+y^2-2x-6y-15=0

radius

x^{2} + y^{2} - 2 x - 6 y - 15 = 0

r = 5

Solution steps

x^{2} + y^{2} - 2 x - 6 y - 15 = 0

Rewrite

x^{2} + y^{2} - 2 x - 6 y - 15 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - 3)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (1, 3), r = 5

And the radius is:

r = 5

(x - 3)^{2} + (y + 4)^{2} = 25

x^{2} + y^{2} + 16 = 9 x

(x + 3)^{2} + (y - 1)^{2} = 9

x^{2} + y^{2} - 14 x - 2 y = 50

(x - 6)^{2} + (y - 2)^{2} = 16