What is the radius (x-5)^2+(y-3)^2=64 ?

The radius (x-5)^2+(y-3)^2=64 is r=8

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radius (x-5)^2+(y-3)^2=64

radius

(x - 5)^{2} + (y - 3)^{2} = 64

r = 8

Solution steps

(x - 5)^{2} + (y - 3)^{2} = 64

Rewrite

(x - 5)^{2} + (y - 3)^{2} = 64

in the form of the standard circle equation

(x - 5)^{2} + (y - 3)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (5, 3), r = 8

And the radius is:

r = 8

x^{2} + (y + 2)^{2} = 36

x^{2} + y^{2} - 2 x - 6 y - 15 = 0

(x - 3)^{2} + (y + 4)^{2} = 25

x^{2} + y^{2} + 16 = 9 x

(x + 3)^{2} + (y - 1)^{2} = 9