What is the radius (x-1)^2+(y+4)^2=16 ?

The radius (x-1)^2+(y+4)^2=16 is r=4

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radius (x-1)^2+(y+4)^2=16

radius

(x - 1)^{2} + (y + 4)^{2} = 16

r = 4

Solution steps

(x - 1)^{2} + (y + 4)^{2} = 16

Rewrite

(x - 1)^{2} + (y + 4)^{2} = 16

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 4))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (1, - 4), r = 4

And the radius is:

r = 4

x^{2} + y^{2} + 2 x - 4 y - 15 = 0

x^{2} + y^{2} - 2 x - 6 y = 71

2 x^{2} + 2 y^{2} - 3 x + 4 y - 35 = 0

(x - 5)^{2} + (y - 3)^{2} = 64

x^{2} + (y + 2)^{2} = 36