What is the radius (x+2)^2+(y-5)^2=25 ?

The radius (x+2)^2+(y-5)^2=25 is r=5

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radius (x+2)^2+(y-5)^2=25

radius

(x + 2)^{2} + (y - 5)^{2} = 25

r = 5

Solution steps

(x + 2)^{2} + (y - 5)^{2} = 25

Rewrite

(x + 2)^{2} + (y - 5)^{2} = 25

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 5)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 2, 5), r = 5

And the radius is:

r = 5

(x + \frac{1}{3})^{2} + (y - 5)^{2} = 7

x^{2} + y^{2} + 8 x - 12 y + 27 = 0

x^{2} + (y - 3)^{2} = 16

(x + 2)^{2} + (y - 5)^{2} = 16

(x - 2)^{2} + (y + 4)^{2} = 9