What is the radius x^2+(y-4)^2=25 ?

The radius x^2+(y-4)^2=25 is r=5

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radius x^2+(y-4)^2=25

radius

x^{2} + (y - 4)^{2} = 25

r = 5

Solution steps

x^{2} + (y - 4)^{2} = 25

Rewrite

x^{2} + (y - 4)^{2} = 25

in the form of the standard circle equation

(x - 0)^{2} + (y - 4)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (0, 4), r = 5

And the radius is:

r = 5

x^{2} + (y - 1)^{2} = 25

x^{2} + y^{2} - 16 = 0

x^{2} + y^{2} - 10 x - 10 y + 25 = 0

x^{2} + y^{2} \leq 1

x^{2} + 4 x + y^{2} - 2 y + 1 = 0