What is the radius x^2+y^2-10x-10y+25=0 ?

The radius x^2+y^2-10x-10y+25=0 is r=5

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radius x^2+y^2-10x-10y+25=0

radius

x^{2} + y^{2} - 10 x - 10 y + 25 = 0

r = 5

Solution steps

x^{2} + y^{2} - 10 x - 10 y + 25 = 0

Rewrite

x^{2} + y^{2} - 10 x - 10 y + 25 = 0

in the form of the standard circle equation

(x - 5)^{2} + (y - 5)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (5, 5), r = 5

And the radius is:

r = 5

x^{2} + y^{2} \leq 1

x^{2} + 4 x + y^{2} - 2 y + 1 = 0

x^{2} + (y - 3)^{2} = 36

x^{2} + y^{2} = \frac{1}{4}

x^{2} + y^{2} - 8 x + 12 y = - 43

What is the radius x^2+y^2-10x-10y+25=0 ?
The radius x^2+y^2-10x-10y+25=0 is r=5