What is the center x^2+y^2-7x=36-4y ?

The center x^2+y^2-7x=36-4y is (7/2 ,-2)

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center x^2+y^2-7x=36-4y

center

x^{2} + y^{2} - 7 x = 36 - 4 y

(\frac{7}{2}, - 2)

Solution steps

x^{2} + y^{2} - 7 x = 36 - 4 y

Rewrite

x^{2} + y^{2} - 7 x = 36 - 4 y

in the form of the standard circle equation

(x - \frac{7}{2})^{2} + (y - (- 2))^{2} = (\frac{209}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{7}{2}, - 2), r = \frac{209}{2}

And the center is:

(\frac{7}{2}, - 2)

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