What is the center 4x^2+4y^2=9 ?

The center 4x^2+4y^2=9 is (0,0)

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center 4x^2+4y^2=9

center

4 x^{2} + 4 y^{2} = 9

(0, 0)

Solution steps

4 x^{2} + 4 y^{2} = 9

Rewrite

4 x^{2} + 4 y^{2} = 9

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (\frac{3}{2})^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = \frac{3}{2}

And the center is:

(0, 0)

x^{2} + y^{2} - 10 x + 10 y + 49 = 0

x^{2} - 4 x + y^{2} + 6 y + 12 = 0

x^{2} + y^{2} - 10 x + 20 y + 61 = 0

(x + 5)^{2} + y^{2} = 25

(X - 5)^{2} + (Y - 6)^{2} = 36