What is the center x^2+6x+y^2-2y-26=0 ?

The center x^2+6x+y^2-2y-26=0 is (-3,1)

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center x^2+6x+y^2-2y-26=0

center

x^{2} + 6 x + y^{2} - 2 y - 26 = 0

(- 3, 1)

Solution steps

x^{2} + 6 x + y^{2} - 2 y - 26 = 0

Rewrite

x^{2} + 6 x + y^{2} - 2 y - 26 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 1)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- 3, 1), r = 6

And the center is:

(- 3, 1)

(x - 1)^{2} + (y + 5)^{2} = 36

3 x^{2} + 3 y^{2} - 6 x + 12 y = 0

x^{2} + y^{2} + 10 x + 6 y + 18 = 0

(x - 4)^{2} + (y - 15)^{2} = 169

(x - 2)^{2} + (y + 5)^{2} = 16