Solution

center

Solution

Solution steps
Rewrite in the form of the standard circle equation
Therefore the circle properties are:
And the center is:

Popular Examples

center (x+2)^2+(y+3)^2=81center center 3x^2+3y^2-18x+6y+2=0center center (x-13)^2+(y+12)^2=64center center x^2+y^2-2/3 x-5/3 y-5/9 =0center center ((x+2)^2)/(16)+((y+5)^2)/(16)=1center

Frequently Asked Questions (FAQ)

  • What is the center x^2+y^2+6x-4y-5=0 ?

    The center x^2+y^2+6x-4y-5=0 is (-3,2)