What is the center x^2+y^2=144 ?

The center x^2+y^2=144 is (0,0)

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center x^2+y^2=144

center

x^{2} + y^{2} = 144

(0, 0)

Solution steps

x^{2} + y^{2} = 144

Rewrite

x^{2} + y^{2} = 144

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 1 2^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 12

And the center is:

(0, 0)

(x + 2)^{2} + y^{2} = 4

x^{2} + y^{2} = 125

x^{2} + y^{2} + 4 x + 4 y = 1

(x + 11)^{2} + (y + 8)^{2} = 147

(x - 5)^{2} + (y - 6)^{2} = 36