What is the center (x-(-5))^2+(y-(7))^2=(sqrt(11))^2 ?

The center (x-(-5))^2+(y-(7))^2=(sqrt(11))^2 is (-5,7)

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center (x-(-5))^2+(y-(7))^2=(sqrt(11))^2

center

(x - (- 5))^{2} + (y - (7))^{2} = (11)^{2}

(- 5, 7)

Solution steps

(x - (- 5))^{2} + (y - 7)^{2} = (11)^{2}

Rewrite

(x - (- 5))^{2} + (y - 7)^{2} = 11^{2}

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 7)^{2} = ((11)^{2})^{2}

Therefore the circle properties are:

(a, b) = (- 5, 7), r = (11)^{2}

And the center is:

(- 5, 7)

(x + 4)^{2} + (y + 1)^{2} = 9

(x + 3)^{2} + (y - 2)^{2} = 25

(x + 3)^{2} + (y - 2)^{2} = 13

(x + 3)^{2} + (y - 2)^{2} = 16

x^{2} + y^{2} + 4 x - 6 y - 23 = 0

What is the center (x-(-5))^2+(y-(7))^2=(sqrt(11))^2 ?
The center (x-(-5))^2+(y-(7))^2=(sqrt(11))^2 is (-5,7)