What is the center 36x^2-36x+36y^2+72y=279 ?

The center 36x^2-36x+36y^2+72y=279 is (1/2 ,-1)

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center 36x^2-36x+36y^2+72y=279

center

36 x^{2} - 36 x + 36 y^{2} + 72 y = 279

(\frac{1}{2}, - 1)

Solution steps

36 x^{2} - 36 x + 36 y^{2} + 72 y = 279

Rewrite

36 x^{2} - 36 x + 36 y^{2} + 72 y = 279

in the form of the standard circle equation

(x - \frac{1}{2})^{2} + (y - (- 1))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{2}, - 1), r = 3

And the center is:

(\frac{1}{2}, - 1)

x^{2} + y^{2} + 6 y + 2 = 0

x^{2} + y^{2} + 6 x - 2 y = 0

x^{2} + y^{2} - 6 x + 12 y + 9 = 9

x^{2} + 7 x + y^{2} - 10 y + 6 = 0

x^{2} + y^{2} + 2 x - 1 y - 4 = 0

What is the center 36x^2-36x+36y^2+72y=279 ?
The center 36x^2-36x+36y^2+72y=279 is (1/2 ,-1)