Solution
center
Solution
Solution steps
Rewrite in the form of the standard circle equation
Therefore the circle properties are:
And the center is:
Popular Examples
center (x-2)^2+(y-4)^2=49center center x^2+y^2+14x-2y+25=0center center (x-1)^2+(y-4)^2=25center center 2(x-2)^2+2y^2=2center center (x+3)^2+(y-4)^2=7center
Frequently Asked Questions (FAQ)
What is the center x^2+y^2+4x+14y+52=0 ?
The center x^2+y^2+4x+14y+52=0 is (-2,-7)