What is the center 3x^2+3y^2=75 ?

The center 3x^2+3y^2=75 is (0,0)

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center 3x^2+3y^2=75

center

3 x^{2} + 3 y^{2} = 75

(0, 0)

Solution steps

3 x^{2} + 3 y^{2} = 75

Rewrite

3 x^{2} + 3 y^{2} = 75

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 5

And the center is:

(0, 0)

x^{2} + y^{2} - 5 x + 4 y - 46 = 0

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x^{2} - 2 x + 3 y + y^{2} - 10 = 0