What is the center x^2+y^2-12x-10y=-12 ?

The center x^2+y^2-12x-10y=-12 is (6,5)

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center x^2+y^2-12x-10y=-12

center

x^{2} + y^{2} - 12 x - 10 y = - 12

(6, 5)

Solution steps

x^{2} + y^{2} - 12 x - 10 y = - 12

Rewrite

x^{2} + y^{2} - 12 x - 10 y = - 12

in the form of the standard circle equation

(x - 6)^{2} + (y - 5)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (6, 5), r = 7

And the center is:

(6, 5)

x^{2} + y^{2} = 5

x^{2} + y^{2} - 4 x = 5

2 x^{2} - 6 x + 2 y^{2} + 2 y = 45

x^{2} + y^{2} - 2 x - 6 y - 15 = 0

x^{2} + 24 x + y^{2} + 10 y = - 160

What is the center x^2+y^2-12x-10y=-12 ?
The center x^2+y^2-12x-10y=-12 is (6,5)