What is x^2+3x+y^2+8x=25 ?

The solution to x^2+3x+y^2+8x=25 is Circle with (a,b)=(-11/2 ,0),r=(sqrt(221))/2

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x^2+3x+y^2+8x=25

x^{2} + 3 x + y^{2} + 8 x = 25

(a, b) = (- \frac{11}{2}, 0), r = \frac{221}{2}

Solution steps

x^{2} + 3 x + y^{2} + 8 x = 25

Rewrite

x^{2} + 3 x + y^{2} + 8 x = 25

in the form of the standard circle equation

(x - (- \frac{11}{2}))^{2} + (y - 0)^{2} = (\frac{221}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{11}{2}, 0), r = \frac{221}{2}

x^{2} + y^{2} + 1 x - 4 y - 8 = 0

x^{2} + (y + 4)^{2} = \frac{3}{5}

(X - 3)^{2} + (Y + 1)^{2} = 6

x^{2} + 4 x = 10 - y^{2}

x^{2} + y^{2} = 6 x + 6 y

What is x^2+3x+y^2+8x=25 ?
The solution to x^2+3x+y^2+8x=25 is Circle with (a,b)=(-11/2 ,0),r=(sqrt(221))/2