What is x^2+y^2-20x-20y+136=0 ?

The solution to x^2+y^2-20x-20y+136=0 is Circle with (a,b)=(10,10),r=8

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x^2+y^2-20x-20y+136=0

x^{2} + y^{2} - 20 x - 20 y + 136 = 0

(a, b) = (10, 10), r = 8

Solution steps

x^{2} + y^{2} - 20 x - 20 y + 136 = 0

Rewrite

x^{2} + y^{2} - 20 x - 20 y + 136 = 0

in the form of the standard circle equation

(x - 10)^{2} + (y - 10)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (10, 10), r = 8

(x - 6)^{2} + (y - 2)^{2} = 3^{2}

a^{2} + b^{2} = 31

a^{2} + b^{2} = 32

4 x^{2} + 4 y^{2} - 20 x - 12 y - 110 = 0

a^{2} + b^{2} = 35

What is x^2+y^2-20x-20y+136=0 ?
The solution to x^2+y^2-20x-20y+136=0 is Circle with (a,b)=(10,10),r=8