What is 2x^2+6x+2y^2+3y-2=0 ?

The solution to 2x^2+6x+2y^2+3y-2=0 is Circle with (a,b)=(-3/2 ,-3/4),r=(sqrt(61))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2x^2+6x+2y^2+3y-2=0

2 x^{2} + 6 x + 2 y^{2} + 3 y - 2 = 0

(a, b) = (- \frac{3}{2}, - \frac{3}{4}), r = \frac{61}{4}

Solution steps

2 x^{2} + 6 x + 2 y^{2} + 3 y - 2 = 0

Rewrite

2 x^{2} + 6 x + 2 y^{2} + 3 y - 2 = 0

in the form of the standard circle equation

(x - (- \frac{3}{2}))^{2} + (y - (- \frac{3}{4}))^{2} = (\frac{61}{4})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{3}{2}, - \frac{3}{4}), r = \frac{61}{4}

4 x^{2} + 4 y^{2} + 40 y + 75 = 0

(- x)^{2} + (- y)^{2} = 14

a^{2} + b^{2} = 52

a^{2} + b^{2} = 58

(x - 3)^{2} + (y - 3)^{2} = 36

What is 2x^2+6x+2y^2+3y-2=0 ?
The solution to 2x^2+6x+2y^2+3y-2=0 is Circle with (a,b)=(-3/2 ,-3/4),r=(sqrt(61))/4