What is 16x^2+16y^2-8x+96y-639=0 ?

The solution to 16x^2+16y^2-8x+96y-639=0 is Circle with (a,b)=(1/4 ,-3),r=7

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16x^2+16y^2-8x+96y-639=0

16 x^{2} + 16 y^{2} - 8 x + 96 y - 639 = 0

(a, b) = (\frac{1}{4}, - 3), r = 7

Solution steps

16 x^{2} + 16 y^{2} - 8 x + 96 y - 639 = 0

Rewrite

16 x^{2} + 16 y^{2} - 8 x + 96 y - 639 = 0

in the form of the standard circle equation

(x - \frac{1}{4})^{2} + (y - (- 3))^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{4}, - 3), r = 7

x^{2} + y^{2} = 38

x^{2} + y^{2} - 12 x - 8 y + 27 = 0

x^{2} + (y + 9)^{2} = 49

4 x^{2} + 4 y^{2} - 8 x - 12 y + 9 = 0

8 x^{2} + 8 y^{2} - 24 + 64 y = 37

What is 16x^2+16y^2-8x+96y-639=0 ?
The solution to 16x^2+16y^2-8x+96y-639=0 is Circle with (a,b)=(1/4 ,-3),r=7