Solution
Solution
Solution steps
Rewrite in the form of the standard circle equation
Therefore the circle properties are:
Popular Examples
4x^2+4y^2+24x-8y-41=0x^2+y^2-6x-12y+36=02x^2+2y^2+15x+15y-15=0(x-2)^{(2)}+(y+1)^{(2)}>= 4(x-2)^2+(y-6)^2=16
Frequently Asked Questions (FAQ)
What is (x+2)^2+y^2=8y-7 ?
The solution to (x+2)^2+y^2=8y-7 is Circle with (a,b)=(-2,4),r=3