What is x^2-16x+64+y^2-14x+49=0 ?

The solution to x^2-16x+64+y^2-14x+49=0 is Circle with (a,b)=(15,0),r=4sqrt(7)

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x^2-16x+64+y^2-14x+49=0

x^{2} - 16 x + 64 + y^{2} - 14 x + 49 = 0

(a, b) = (15, 0), r = 47

Solution steps

x^{2} - 16 x + 64 + y^{2} - 14 x + 49 = 0

Rewrite

x^{2} - 16 x + 64 + y^{2} - 14 x + 49 = 0

in the form of the standard circle equation

(x - 15)^{2} + (y - 0)^{2} = (47)^{2}

Therefore the circle properties are:

(a, b) = (15, 0), r = 47

5 x^{2} - 5 x + 5 y^{2} - 4 y - 9 = 0

x^{2} - 2 x + y^{2} = 15

x^{2} + y^{2} \leq 4 x + 4 y

3 x^{2} + 3 y^{2} = y + 2

x^{2} + (y - 115)^{2} = 11025

What is x^2-16x+64+y^2-14x+49=0 ?
The solution to x^2-16x+64+y^2-14x+49=0 is Circle with (a,b)=(15,0),r=4sqrt(7)