What is 17=(x-1)^2+(y+1)^2 ?

The solution to 17=(x-1)^2+(y+1)^2 is Circle with (a,b)=(1,-1),r=sqrt(17)

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17=(x-1)^2+(y+1)^2

17 = (x - 1)^{2} + (y + 1)^{2}

(a, b) = (1, - 1), r = 17

Solution steps

17 = (x - 1)^{2} + (y + 1)^{2}

Rewrite

17 = (x - 1)^{2} + (y + 1)^{2}

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 1))^{2} = (17)^{2}

Therefore the circle properties are:

(a, b) = (1, - 1), r = 17

(x - 8)^{2} + (y + 3)^{2} = 91

x^{2} + y^{2} - 12 x - 10 y - 15 = 0

\frac{3}{2} x^{2} + \frac{3}{2} y^{2} = \frac{75}{2}

16 x^{2} + 16 y^{2} + 8 x - 32 = - 1

4^{2} = (x + 4)^{2} + (y - 0)^{2}

What is 17=(x-1)^2+(y+1)^2 ?
The solution to 17=(x-1)^2+(y+1)^2 is Circle with (a,b)=(1,-1),r=sqrt(17)