What is (x+8)^2+(y+2)^2=36 ?

The solution to (x+8)^2+(y+2)^2=36 is Circle with (a,b)=(-8,-2),r=6

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(x+8)^2+(y+2)^2=36

(x + 8)^{2} + (y + 2)^{2} = 36

(a, b) = (- 8, - 2), r = 6

Solution steps

(x + 8)^{2} + (y + 2)^{2} = 36

Rewrite

(x + 8)^{2} + (y + 2)^{2} = 36

in the form of the standard circle equation

(x - (- 8))^{2} + (y - (- 2))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- 8, - 2), r = 6

x^{2} - 2 x + y^{2} - 8 = 0

x^{2} - 14 x + y^{2} + 2 y + 50 = 4

x^{2} + y^{2} + 6 x - 47 = 387

x^{2} + y^{2} - 6 x - 3 y - 12 = 0

x^{2} - 12 x + y^{2} - 18 y + 92 = 0

What is (x+8)^2+(y+2)^2=36 ?
The solution to (x+8)^2+(y+2)^2=36 is Circle with (a,b)=(-8,-2),r=6