What is x^2-12x+y^2-2y-12=0 ?

The solution to x^2-12x+y^2-2y-12=0 is Circle with (a,b)=(6,1),r=7

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x^2-12x+y^2-2y-12=0

x^{2} - 12 x + y^{2} - 2 y - 12 = 0

(a, b) = (6, 1), r = 7

Solution steps

x^{2} - 12 x + y^{2} - 2 y - 12 = 0

Rewrite

x^{2} - 12 x + y^{2} - 2 y - 12 = 0

in the form of the standard circle equation

(x - 6)^{2} + (y - 1)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (6, 1), r = 7

3 x^{2} + 3 y^{2} - 12 x - 48 y = 0

(x - \frac{3}{5})^{2} + (y - \frac{1}{3})^{2} = 10^{2}

x^{2} + 10 x + y^{2} - 4 - 8 = 12

4 (x + 1)^{2} + 4 (y)^{2} = 121

(x - 5)^{2} + (y + 3)^{2} = 73

What is x^2-12x+y^2-2y-12=0 ?
The solution to x^2-12x+y^2-2y-12=0 is Circle with (a,b)=(6,1),r=7