What is 3x^2+3y^2-12x-48y=0 ?

The solution to 3x^2+3y^2-12x-48y=0 is Circle with (a,b)=(2,8),r=2sqrt(17)

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3x^2+3y^2-12x-48y=0

3 x^{2} + 3 y^{2} - 12 x - 48 y = 0

(a, b) = (2, 8), r = 217

Solution steps

3 x^{2} + 3 y^{2} - 12 x - 48 y = 0

Rewrite

3 x^{2} + 3 y^{2} - 12 x - 48 y = 0

in the form of the standard circle equation

(x - 2)^{2} + (y - 8)^{2} = (217)^{2}

Therefore the circle properties are:

(a, b) = (2, 8), r = 217

(x - \frac{3}{5})^{2} + (y - \frac{1}{3})^{2} = 10^{2}

x^{2} + 10 x + y^{2} - 4 - 8 = 12

4 (x + 1)^{2} + 4 (y)^{2} = 121

(x - 5)^{2} + (y + 3)^{2} = 73

(x + 4)^{2} + (y - 3)^{2} = 16

What is 3x^2+3y^2-12x-48y=0 ?
The solution to 3x^2+3y^2-12x-48y=0 is Circle with (a,b)=(2,8),r=2sqrt(17)