What is 16x^2+16y^2+98x-40y=315 ?

The solution to 16x^2+16y^2+98x-40y=315 is Circle with (a,b)=(-49/16 , 5/4),r=(sqrt(7841))/(16)

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16x^2+16y^2+98x-40y=315

16 x^{2} + 16 y^{2} + 98 x - 40 y = 315

(a, b) = (- \frac{49}{16}, \frac{5}{4}), r = \frac{7841}{16}

Solution steps

16 x^{2} + 16 y^{2} + 98 x - 40 y = 315

Rewrite

16 x^{2} + 16 y^{2} + 98 x - 40 y = 315

in the form of the standard circle equation

(x - (- \frac{49}{16}))^{2} + (y - \frac{5}{4})^{2} = (\frac{7841}{16})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{49}{16}, \frac{5}{4}), r = \frac{7841}{16}

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What is 16x^2+16y^2+98x-40y=315 ?
The solution to 16x^2+16y^2+98x-40y=315 is Circle with (a,b)=(-49/16 , 5/4),r=(sqrt(7841))/(16)