What is (x-1/2)^2+(y+1/4)^2= 64/25 ?

The solution to (x-1/2)^2+(y+1/4)^2= 64/25 is Circle with (a,b)=(1/2 ,-1/4),r= 8/5

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(x-1/2)^2+(y+1/4)^2= 64/25

(x - \frac{1}{2})^{2} + (y + \frac{1}{4})^{2} = \frac{64}{25}

(a, b) = (\frac{1}{2}, - \frac{1}{4}), r = \frac{8}{5}

Solution steps

(x - \frac{1}{2})^{2} + (y + \frac{1}{4})^{2} = \frac{64}{25}

Rewrite

(x - \frac{1}{2})^{2} + (y + \frac{1}{4})^{2} = \frac{64}{25}

in the form of the standard circle equation

(x - \frac{1}{2})^{2} + (y - (- \frac{1}{4}))^{2} = (\frac{8}{5})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{2}, - \frac{1}{4}), r = \frac{8}{5}

x^{2} - 6 x + y^{2} - 10 y = 2

x^{2} + y^{2} - 21 = 0

5 x^{2} + 5 y^{2} - 36 x + 98 y - 1 = 0

(x - 5)^{2} + (y - 2)^{2} = 1

x, x^{2} + 400 x + p (x)^{2} + 250 p = 60000

What is (x-1/2)^2+(y+1/4)^2= 64/25 ?
The solution to (x-1/2)^2+(y+1/4)^2= 64/25 is Circle with (a,b)=(1/2 ,-1/4),r= 8/5