What is (((x+2)^2))/4+(((y+4)^2))/4 =1 ?

The solution to (((x+2)^2))/4+(((y+4)^2))/4 =1 is Circle with (a,b)=(-2,-4),r=2

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(((x+2)^2))/4+(((y+4)^2))/4 =1

\frac{( ( x + 2 ) ^{2} )}{4} + \frac{( ( y + 4 ) ^{2} )}{4} = 1

(a, b) = (- 2, - 4), r = 2

Solution steps

\frac{( x + 2 ) ^{2}}{4} + \frac{( y + 4 ) ^{2}}{4} = 1

Rewrite

\frac{( x + 2 ) ^{2}}{4} + \frac{( y + 4 ) ^{2}}{4} = 1

in the form of the standard circle equation

(x - (- 2))^{2} + (y - (- 4))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 2, - 4), r = 2

y^{2} = 36 - x^{2}

(x - \frac{1}{2})^{2} + (y + \frac{1}{4})^{2} = \frac{64}{25}

x^{2} - 6 x + y^{2} - 10 y = 2

x^{2} + y^{2} - 21 = 0

5 x^{2} + 5 y^{2} - 36 x + 98 y - 1 = 0

What is (((x+2)^2))/4+(((y+4)^2))/4 =1 ?
The solution to (((x+2)^2))/4+(((y+4)^2))/4 =1 is Circle with (a,b)=(-2,-4),r=2