What is 10x^2+10y^2-200=0 ?

The solution to 10x^2+10y^2-200=0 is Circle with (a,b)=(0,0),r=2sqrt(5)

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10x^2+10y^2-200=0

10 x^{2} + 10 y^{2} - 200 = 0

(a, b) = (0, 0), r = 25

Solution steps

10 x^{2} + 10 y^{2} - 200 = 0

Rewrite

10 x^{2} + 10 y^{2} - 200 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (25)^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 25

(x + 6)^{2} + (y + 14)^{2} = 100

3 x^{2} + 3 y^{2} + 12 x - 22 y + 35 = 0

2 x^{2} - 12 x + 2 y^{2} + 6 y = \frac{19}{2}

(x + 4)^{2} + (y - 2)^{2} = 3

(x + 4)^{2} + (y - 2)^{2} = 2

What is 10x^2+10y^2-200=0 ?
The solution to 10x^2+10y^2-200=0 is Circle with (a,b)=(0,0),r=2sqrt(5)