What is (x+6)^2+(y+14)^2=100 ?

The solution to (x+6)^2+(y+14)^2=100 is Circle with (a,b)=(-6,-14),r=10

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(x+6)^2+(y+14)^2=100

(x + 6)^{2} + (y + 14)^{2} = 100

(a, b) = (- 6, - 14), r = 10

Solution steps

(x + 6)^{2} + (y + 14)^{2} = 100

Rewrite

(x + 6)^{2} + (y + 14)^{2} = 100

in the form of the standard circle equation

(x - (- 6))^{2} + (y - (- 14))^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (- 6, - 14), r = 10

3 x^{2} + 3 y^{2} + 12 x - 22 y + 35 = 0

2 x^{2} - 12 x + 2 y^{2} + 6 y = \frac{19}{2}

(x + 4)^{2} + (y - 2)^{2} = 3

(x + 4)^{2} + (y - 2)^{2} = 2

(x + 4)^{2} + (y - 2)^{2} = 1

What is (x+6)^2+(y+14)^2=100 ?
The solution to (x+6)^2+(y+14)^2=100 is Circle with (a,b)=(-6,-14),r=10