What is 3x^2=-3y^2+12 ?

The solution to 3x^2=-3y^2+12 is Circle with (a,b)=(0,0),r=2

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3x^2=-3y^2+12

3 x^{2} = - 3 y^{2} + 12

(a, b) = (0, 0), r = 2

Solution steps

3 x^{2} = - 3 y^{2} + 12

Rewrite

3 x^{2} = - 3 y^{2} + 12

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 2

(x - 3)^{(2)} + (y + 2)^{(2)} = 3

x^{2} + y^{2} - 2 \geq 0

u^{2} + y^{2} = 146

4 x^{2} + 4 y^{2} + 0 = 16

x^{2} + y^{2} + 10 x - 16 y - 11 = 0

What is 3x^2=-3y^2+12 ?
The solution to 3x^2=-3y^2+12 is Circle with (a,b)=(0,0),r=2