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Beliebt Geometry >

16x^2+25y^2=400

Lösung

16 x^{2} + 25 y^{2} = 400

Lösung

(h, k) = (0, 0), a = 5, b = 4

Schritte zur Lösung

16 x^{2} + 25 y^{2} = 400

Rewrite

16 x^{2} + 25 y^{2} = 400

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 5, b = 4

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 5, b = 4

Graph

Beliebte Beispiele

foki (x^2}{25}+\frac{y^2)/9 =1

f oc i \frac{x ^{2}}{25} + \frac{y ^{2}}{9} = 1

scheitelpunkte 9x^2-4y^2=36

v er t i ces 9 x^{2} - 4 y^{2} = 36

foki (x^2)/4-(y^2)/(16)=1

f oc i \frac{x ^{2}}{4} - \frac{y ^{2}}{16} = 1

x^{2} - y^{2} = 3

9x^2+4y^2-18x+16y-11=0

9 x^{2} + 4 y^{2} - 18 x + 16 y - 11 = 0