What is x^2+(y-1)^2=7 ?

The solution to x^2+(y-1)^2=7 is Circle with (a,b)=(0,1),r=sqrt(7)

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x^2+(y-1)^2=7

x^{2} + (y - 1)^{2} = 7

(a, b) = (0, 1), r = 7

Solution steps

x^{2} + (y - 1)^{2} = 7

Rewrite

x^{2} + (y - 1)^{2} = 7

in the form of the standard circle equation

(x - 0)^{2} + (y - 1)^{2} = (7)^{2}

Therefore the circle properties are:

(a, b) = (0, 1), r = 7

x^{2} + (y + 5)^{2} = 61

x^{2} - 4 x + y^{2} - 6 y + 8 = 0

(x + 2)^{(2)} + (y - 1)^{(2)} = 3

3 x^{2} = - 3 y^{2} + 75

x^{(2)} + 10 x + y^{(2)} - 2 y = 10

What is x^2+(y-1)^2=7 ?
The solution to x^2+(y-1)^2=7 is Circle with (a,b)=(0,1),r=sqrt(7)