What is (x+2)^{(2)}+(y-1)^{(2)}=3 ?

The solution to (x+2)^{(2)}+(y-1)^{(2)}=3 is Circle with (a,b)=(-2,1),r=sqrt(3)

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(x+2)^{(2)}+(y-1)^{(2)}=3

(x + 2)^{(2)} + (y - 1)^{(2)} = 3

(a, b) = (- 2, 1), r = 3

Solution steps

(x + 2)^{2} + (y - 1)^{2} = 3

Rewrite

(x + 2)^{2} + (y - 1)^{2} = 3

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 1)^{2} = (3)^{2}

Therefore the circle properties are:

(a, b) = (- 2, 1), r = 3

3 x^{2} = - 3 y^{2} + 75

x^{(2)} + 10 x + y^{(2)} - 2 y = 10

x^{2} - 18 x + 29 + y^{2} = 0

3 x^{2} > 12 - 3 y^{2}

x^{2} + y^{2} - 16 x - 18 y + 109 = 0

What is (x+2)^{(2)}+(y-1)^{(2)}=3 ?
The solution to (x+2)^{(2)}+(y-1)^{(2)}=3 is Circle with (a,b)=(-2,1),r=sqrt(3)