What is x^2+y^2=(3sqrt(3))^2 ?

The solution to x^2+y^2=(3sqrt(3))^2 is Circle with (a,b)=(0,0),r=sqrt((3\sqrt{3))^2}

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x^2+y^2=(3sqrt(3))^2

x^{2} + y^{2} = (33)^{2}

(a, b) = (0, 0), r = (33)^{2}

Solution steps

x^{2} + y^{2} = (33)^{2}

Rewrite

x^{2} + y^{2} = (33)^{2}

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = ((33)^{2})^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = (33)^{2}

(x - 4)^{2} + (y - 1)^{2} = 14

3 x^{2} + 3 y^{2} - 18 x + 6 y + 2 = 0

\frac{4 ( x + \frac{5}{2} ) ^{2}}{45} + \frac{4 ( y - 2 ) ^{2}}{45} = 1

x^{2} + (y - 1)^{2} = 2

x^{2} + (y - 1)^{2} = 7

What is x^2+y^2=(3sqrt(3))^2 ?
The solution to x^2+y^2=(3sqrt(3))^2 is Circle with (a,b)=(0,0),r=sqrt((3\sqrt{3))^2}