What is ((x+2)^2)/3+(z^2)/3 =3 ?

The solution to ((x+2)^2)/3+(z^2)/3 =3 is Circle with (a,b)=(-2,0),r=3

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((x+2)^2)/3+(z^2)/3 =3

\frac{( x + 2 ) ^{2}}{3} + \frac{z ^{2}}{3} = 3

(a, b) = (- 2, 0), r = 3

Solution steps

\frac{( x + 2 ) ^{2}}{3} + \frac{z ^{2}}{3} = 3

Rewrite

\frac{( x + 2 ) ^{2}}{3} + \frac{z ^{2}}{3} = 3

in the form of the standard circle equation

(x - (- 2))^{2} + (z - 0)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 2, 0), r = 3

x^{2} + y^{2} + 4 x - 6 y - 26 = 0

12 X^{2} + 12 Y^{2} = 144

2. 3^{2} = (x + 3)^{2} + (y - 1)^{2}

(x + 1)^{2} + (y + 3)^{2} = 4

2 x^{2} + 2 y^{2} = 11

What is ((x+2)^2)/3+(z^2)/3 =3 ?
The solution to ((x+2)^2)/3+(z^2)/3 =3 is Circle with (a,b)=(-2,0),r=3