What is x^2-2x+y^2+4y=10 ?

The solution to x^2-2x+y^2+4y=10 is Circle with (a,b)=(1,-2),r=sqrt(15)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2-2x+y^2+4y=10

x^{2} - 2 x + y^{2} + 4 y = 10

(a, b) = (1, - 2), r = 15

Solution steps

x^{2} - 2 x + y^{2} + 4 y = 10

Rewrite

x^{2} - 2 x + y^{2} + 4 y = 10

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 2))^{2} = (15)^{2}

Therefore the circle properties are:

(a, b) = (1, - 2), r = 15

x^{2} - 4 x + y^{2} - 4 - 8 = 0

(x - 4)^{2} + (y + 12)^{2} + (0 - 8)^{2} = 100

(x - 0)^{2} + (y - 4)^{2} = 5^{2}

(x - 0)^{2} + (y - 0)^{2} = 162

(x - 0)^{2} + (y - 0)^{2} = 169

What is x^2-2x+y^2+4y=10 ?
The solution to x^2-2x+y^2+4y=10 is Circle with (a,b)=(1,-2),r=sqrt(15)