What is 2x^2-4x+2y^2+18y=7 ?

The solution to 2x^2-4x+2y^2+18y=7 is Circle with (a,b)=(1,-9/2),r=(3sqrt(11))/2

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2x^2-4x+2y^2+18y=7

2 x^{2} - 4 x + 2 y^{2} + 18 y = 7

(a, b) = (1, - \frac{9}{2}), r = \frac{3 11}{2}

Solution steps

2 x^{2} - 4 x + 2 y^{2} + 18 y = 7

Rewrite

2 x^{2} - 4 x + 2 y^{2} + 18 y = 7

in the form of the standard circle equation

(x - 1)^{2} + (y - (- \frac{9}{2}))^{2} = (\frac{3 11}{2})^{2}

Therefore the circle properties are:

(a, b) = (1, - \frac{9}{2}), r = \frac{3 11}{2}

(x - 1)^{2} + y^{2} - 1 = \frac{3}{6} x

(x - 6)^{2} + (y - 10)^{2} = 5

2 x^{2} + 2 y^{2} + 8 x - 8 y = 34

x^{2} + y^{2} - 4 - 2 x - 4 y = 0

(x - 2)^{2} + (y + 3)^{2} = 4^{2}

What is 2x^2-4x+2y^2+18y=7 ?
The solution to 2x^2-4x+2y^2+18y=7 is Circle with (a,b)=(1,-9/2),r=(3sqrt(11))/2