What is -y^2=(x+2)(x-3) ?

The solution to -y^2=(x+2)(x-3) is Circle with (a,b)=(1/2 ,0),r= 5/2

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-y^2=(x+2)(x-3)

- y^{2} = (x + 2) (x - 3)

(a, b) = (\frac{1}{2}, 0), r = \frac{5}{2}

Solution steps

- y^{2} = (x + 2) (x - 3)

Rewrite

- y^{2} = (x + 2) (x - 3)

in the form of the standard circle equation

(x - \frac{1}{2})^{2} + (y - 0)^{2} = (\frac{5}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{2}, 0), r = \frac{5}{2}

x^{2} - 4 x + y^{2} - 10 y = 35

(x_{+ 2})^{2} + (y + 1)^{2} = 16

x^{2} - x + y^{2} + 9 y + 11 = 0

(x + 7)^{2} + (y - 4)^{2} = 50

(x - 4)^{2} + (y - 7)^{2} = 100

What is -y^2=(x+2)(x-3) ?
The solution to -y^2=(x+2)(x-3) is Circle with (a,b)=(1/2 ,0),r= 5/2