What is x^2+y^2-16x+8y+64=0 ?

The solution to x^2+y^2-16x+8y+64=0 is Circle with (a,b)=(8,-4),r=4

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x^2+y^2-16x+8y+64=0

x^{2} + y^{2} - 16 x + 8 y + 64 = 0

(a, b) = (8, - 4), r = 4

Solution steps

x^{2} + y^{2} - 16 x + 8 y + 64 = 0

Rewrite

x^{2} + y^{2} - 16 x + 8 y + 64 = 0

in the form of the standard circle equation

(x - 8)^{2} + (y - (- 4))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (8, - 4), r = 4

4 x^{2} + 4 y^{2} - 6 x + 10 y = \frac{1}{2}

(x + 15)^{2} + (y - 12)^{2} = 64

x^{2} + y^{2} = 1

(x - 2)^{2} + (y + 4)^{2} = 36

4 x^{2} + 4 y^{2} - 40 x - 8 y + 40 = 0

What is x^2+y^2-16x+8y+64=0 ?
The solution to x^2+y^2-16x+8y+64=0 is Circle with (a,b)=(8,-4),r=4