What is x^2+4x+y^2+6y=16 ?

The solution to x^2+4x+y^2+6y=16 is Circle with (a,b)=(-2,-3),r=sqrt(29)

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x^2+4x+y^2+6y=16

x^{2} + 4 x + y^{2} + 6 y = 16

(a, b) = (- 2, - 3), r = 29

Solution steps

x^{2} + 4 x + y^{2} + 6 y = 16

Rewrite

x^{2} + 4 x + y^{2} + 6 y = 16

in the form of the standard circle equation

(x - (- 2))^{2} + (y - (- 3))^{2} = (29)^{2}

Therefore the circle properties are:

(a, b) = (- 2, - 3), r = 29

(x - 3)^{2} + (y + 2)^{2} = 33

4 x^{2} + 4 y^{2} - 24 x + 36 y = - 81

4 x^{2} - 8 x + 4 y^{2} - 16 y - 124 = 0

x^{2} + y^{2} - 14 x + 12 y + 59 = 0

x^{2} + y^{2} + 10 x + 4 y - 56 = 0

What is x^2+4x+y^2+6y=16 ?
The solution to x^2+4x+y^2+6y=16 is Circle with (a,b)=(-2,-3),r=sqrt(29)