What is (x-2)^2+(y+9)^2=196 ?

The solution to (x-2)^2+(y+9)^2=196 is Circle with (a,b)=(2,-9),r=14

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(x-2)^2+(y+9)^2=196

(x - 2)^{2} + (y + 9)^{2} = 196

(a, b) = (2, - 9), r = 14

Solution steps

(x - 2)^{2} + (y + 9)^{2} = 196

Rewrite

(x - 2)^{2} + (y + 9)^{2} = 196

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 9))^{2} = 1 4^{2}

Therefore the circle properties are:

(a, b) = (2, - 9), r = 14

(x - 3)^{2} + (y + 8)^{2} = 65

(x - 4)^{2} + (y + 10)^{2} = 81

x^{2} + y^{2} + 14 x - 10 y + 65 = 0 x

3 x^{2} + 3 y^{2} - 30 x - 6 y + 75 = 0

0.2 x^{2} + x + 0.2 y^{2} - 4 y = 1

What is (x-2)^2+(y+9)^2=196 ?
The solution to (x-2)^2+(y+9)^2=196 is Circle with (a,b)=(2,-9),r=14