What is (x+1)^2+(y+8)^2=14 ?

The solution to (x+1)^2+(y+8)^2=14 is Circle with (a,b)=(-1,-8),r=sqrt(14)

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(x+1)^2+(y+8)^2=14

(x + 1)^{2} + (y + 8)^{2} = 14

(a, b) = (- 1, - 8), r = 14

Solution steps

(x + 1)^{2} + (y + 8)^{2} = 14

Rewrite

(x + 1)^{2} + (y + 8)^{2} = 14

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- 8))^{2} = (14)^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 8), r = 14

(x - \frac{1}{2})^{2} + (y)^{2} = \frac{1}{4}

(x - 5)^{2} + (y + 5)^{2} = 9

(x)^{2} + (y)^{2} = 9

x^{2} + y^{2} - 10 x - 6 y = 5

x^{2} - 6 x + y^{2} - 27 = 0

What is (x+1)^2+(y+8)^2=14 ?
The solution to (x+1)^2+(y+8)^2=14 is Circle with (a,b)=(-1,-8),r=sqrt(14)