What is (x-1/2)^2+(y)^2= 1/4 ?

The solution to (x-1/2)^2+(y)^2= 1/4 is Circle with (a,b)=(1/2 ,0),r= 1/2

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(x-1/2)^2+(y)^2= 1/4

(x - \frac{1}{2})^{2} + (y)^{2} = \frac{1}{4}

(a, b) = (\frac{1}{2}, 0), r = \frac{1}{2}

Solution steps

(x - \frac{1}{2})^{2} + y^{2} = \frac{1}{4}

Rewrite

(x - \frac{1}{2})^{2} + y^{2} = \frac{1}{4}

in the form of the standard circle equation

(x - \frac{1}{2})^{2} + (y - 0)^{2} = (\frac{1}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{2}, 0), r = \frac{1}{2}

(x - 5)^{2} + (y + 5)^{2} = 9

(x)^{2} + (y)^{2} = 9

x^{2} + y^{2} - 10 x - 6 y = 5

x^{2} - 6 x + y^{2} - 27 = 0

4 x^{2} - 8 x + 4 y^{2} + 28 y = 11

What is (x-1/2)^2+(y)^2= 1/4 ?
The solution to (x-1/2)^2+(y)^2= 1/4 is Circle with (a,b)=(1/2 ,0),r= 1/2