What is (-1-x)^2+(2-y)^2=25 ?

The solution to (-1-x)^2+(2-y)^2=25 is Circle with (a,b)=(-1,2),r=5

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(-1-x)^2+(2-y)^2=25

(- 1 - x)^{2} + (2 - y)^{2} = 25

(a, b) = (- 1, 2), r = 5

Solution steps

(- 1 - x)^{2} + (2 - y)^{2} = 25

Rewrite

(- 1 - x)^{2} + (2 - y)^{2} = 25

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 2)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 1, 2), r = 5

(x - 15)^{2} + (y + 7)^{2} = 7^{2}

15 x^{2} + 15 y^{2} = 60

x^{2} + y^{2} - 6 x + \frac{80}{9} = 0

x - y + x^{2} + y^{2} = 17

x^{2} + y^{2} + x - 4 y - 11 = 0

What is (-1-x)^2+(2-y)^2=25 ?
The solution to (-1-x)^2+(2-y)^2=25 is Circle with (a,b)=(-1,2),r=5