What is (x-15)^2+(y+7)^2=7^2 ?

The solution to (x-15)^2+(y+7)^2=7^2 is Circle with (a,b)=(15,-7),r=7

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(x-15)^2+(y+7)^2=7^2

(x - 15)^{2} + (y + 7)^{2} = 7^{2}

(a, b) = (15, - 7), r = 7

Solution steps

(x - 15)^{2} + (y + 7)^{2} = 7^{2}

Rewrite

(x - 15)^{2} + (y + 7)^{2} = 7^{2}

in the form of the standard circle equation

(x - 15)^{2} + (y - (- 7))^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (15, - 7), r = 7

15 x^{2} + 15 y^{2} = 60

x^{2} + y^{2} - 6 x + \frac{80}{9} = 0

x - y + x^{2} + y^{2} = 17

x^{2} + y^{2} + x - 4 y - 11 = 0

x^{2} + y^{2} + 2 x + 4 y + \frac{1}{3} > 0

What is (x-15)^2+(y+7)^2=7^2 ?
The solution to (x-15)^2+(y+7)^2=7^2 is Circle with (a,b)=(15,-7),r=7