What is (x-4)^2+(y+7)^2=8 ?

The solution to (x-4)^2+(y+7)^2=8 is Circle with (a,b)=(4,-7),r=sqrt(8)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-4)^2+(y+7)^2=8

(x - 4)^{2} + (y + 7)^{2} = 8

(a, b) = (4, - 7), r = 8

Solution steps

(x - 4)^{2} + (y + 7)^{2} = 8

Rewrite

(x - 4)^{2} + (y + 7)^{2} = 8

in the form of the standard circle equation

(x - 4)^{2} + (y - (- 7))^{2} = (8)^{2}

Therefore the circle properties are:

(a, b) = (4, - 7), r = 8

4 x^{2} - 24 x + 4 y^{2} + 72 y = 76

(x - 3)^{2} + (y - 5)^{2} - 54 = 0

(x - (- 3))^{2} + (y - 0)^{2} = 6^{2}

(x - 6)^{(2)} + (y + 2)^{(2)} = 5

(x + 4)^{2} + (y + 1)^{2} = 30

What is (x-4)^2+(y+7)^2=8 ?
The solution to (x-4)^2+(y+7)^2=8 is Circle with (a,b)=(4,-7),r=sqrt(8)